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Allowance
這題蠻有趣的,有空補個思路
code
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#include <iostream>
#include <functional>
#include <vector>
#include <algorithm>
#include <utility>
#define PB push_back
#define MP make_pair
#define X first
#define Y second
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;
vector<pll> v;
vector<pll>::iterator vi;
ll N, C, a, b, ans, sum;
ll cnt[30], curr, tmp;
int main(){
cin>>N>>C;
while(N--){
cin>>a>>b;
if(a >= C) ans+=b;
else{
v.PB(MP(a,b));
sum += (a*b);
}
}
sort(v.begin(), v.end(), greater<pll>());
while(sum >= C){
curr = C;
for(vi = v.begin(); vi != v.end();)
(*vi).Y == 0 ? v.erase(vi) : vi++ ;
for(int i=0;i<v.size();i++){
cnt[i] = min(v[i].Y, curr/v[i].X);
curr -= (cnt[i]*v[i].X);
}
for(int i=v.size()-1; i>=0 && curr>0 ; i--)if(v[i].Y - cnt[i]){
tmp = min(v[i].Y-cnt[i], (curr+v[i].X-1)/v[i].X);
cnt[i] += tmp;
curr -= (tmp * v[i].X);
}
tmp = (1<<30);
for(int i=0;i<v.size();i++)if(cnt[i])
tmp = min(tmp, v[i].Y/cnt[i]);
for(int i=0;i<v.size();i++)if(cnt[i]){
v[i].Y -= (tmp*cnt[i]);
sum -= (tmp*cnt[i]*v[i].X);
}
ans+=tmp;
}
cout<<ans<<endl;
}