傳送門:
Bad Cowtractors
思路:
有點變化的MST,權重轉負套上一題 code 殺掉即可。
code:
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struct Node{
int f, t, l;
Node(int F=0, int T=0, int L=0):
f(F), t(T), l(L){}
inline bool operator < (const Node& a)const{
return l<a.l;
}
}e[20005];
int T,M,N,K,I,a,b,c,ans,cnt;
int par[1005];
void init(){
ans = cnt = 0;
N = getint(), M = getint();
for(int i=0;i<N;i++) par[i] = i;
for(int i=0;i<M;i++){
a = getint(), b = getint(), c = getint();
e[i] = Node(a-1,b-1,-c);
}
}
int _find(int v){
return ( par[v]==v ? v : par[v]= _find(par[v]));
}
void sol(){
int t1, t2;
sort(e, e+M);
for(int i=0;i<M;i++){
t1 = _find(e[i].f), t2 = _find(e[i].t);
if(t1 == t2) continue;
cnt ++ ;
ans -= e[i].l;
(i&1) ? par[t1] = t2 : par[t2] = t1;
}
if(cnt < N-1) puts("-1");
else printf("%d\n", ans);
}
int main(){
init();
sol();
}